当前位置: 首页 > 图文教程 > 网络编程 > ASP > 如何用asp进行base64加密

ASP
ASP实例:是否支持XmlHttp组件的判断
ASP对XML文档中文本的增加、删除、修改、查看
ASP操作XML文件的主要方法和实现
asp控制xml数据库的6段代码
ASP操作XML的类
ASP关于类的Let,Set和Get的用法的异同
ASP错误解决:800a003a错误
XMLHTTP Post Form时的表单乱码
IIS7.0在Vista系统下安装注意事项
asp文件打不开的原因
asp根据表单自动生成sql语句的函数
彻底解决XP下IIS无法解释ASP和PHP的问题
ASP教程:0177:800401f3错误解决
Service Unavailable错误的解决
ASP留言本教程
ASP教程:6大对象和数据库操作简单学
配置IIS蜜罐与黑客攻击
WEB共享与IIS相结合快速建立本地网站
IIS6架设网站的问题总结
HTTP 500 - 内部服务器错误的解决

ASP 中的 如何用asp进行base64加密


出处:互联网   整理: 软晨网(RuanChen.com)   发布: 2009-11-03   浏览: 185 ::
收藏到网摘: n/a

  <%
     OPTION EXPLICIT
     const BASE_64_MAP_INIT =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
     dim nl
     ' zero based arrays
     dim Base64EncMap(63)
     dim Base64DecMap(127)

     ' must be called before using anything else
     PUBLIC SUB initCodecs()
          ' init vars
          nl = "<P>" & chr(13) & chr(10)
          ' setup base 64
          dim max, idx
             max = len(BASE_64_MAP_INIT)
          for idx = 0 to max - 1
               ' one based string
               Base64EncMap(idx) = mid(BASE_64_MAP_INIT, idx + 1, 1)
          next
          for idx = 0 to max - 1
               Base64DecMap(ASC(Base64EncMap(idx))) = idx
          next
     END SUB

     ' encode base 64 encoded string
     PUBLIC FUNCTION base64Encode(plain)

          if len(plain) = 0 then
               base64Encode = ""
               exit function
          end if

          dim ret, ndx, by3, first, second, third
          by3 = (len(plain) \ 3) * 3
          ndx = 1
          do while ndx <= by3
               first  = asc(mid(plain, ndx+0, 1))
               second = asc(mid(plain, ndx+1, 1))
               third  = asc(mid(plain, ndx+2, 1))
               ret = ret & Base64EncMap(  (first \ 4) AND 63 )
               ret = ret & Base64EncMap( ((first * 16) AND 48) + ((second \ 16)
AND 15 ) )
               ret = ret & Base64EncMap( ((second * 4) AND 60) + ((third \ 64)
AND 3 ) )
               ret = ret & Base64EncMap( third AND 63)
               ndx = ndx + 3
          loop
          ' check for stragglers
          if by3 < len(plain) then
            &