繁體中文当前位置: 首页 > 图文教程 > 数据库 > MYSQL > MySQL 查找价格最高的图书经销商的几种SQL语句
- MYSQL
- 如何恢复/修复MS SQL数据库的MDF文件
- DB2 基础：日期和时间的使用
- MYSQL到ORACLE程序迁移的注意事项
- Eclipse+JBoss+MySQL开发环境设置全攻略
- 剖析数据库特性：滞后联编和对象嵌套
- 用户认证功能的SQUID代理服务器
- 教你怎样正确配置MySQL数据库SQL Mail
- MYSQL的master/slave数据同步配置
- 让MySQL与OpenOffice共舞
- MySQL两种表存储结构性能比较测试过程
- 帮助你开发基于MySQL数据库的论坛设计
- 用MySQL创建数据库和数据库表
- 最简便的备份MySql数据库方法
- Word域与数据库的结合编程
- 带你轻松接触一个检测MySQL状态的脚本
- 如何配置MySQL数据库主从复制
- 在服务器上安装使用MySQL的注意事项
- 轻松掌握怎样测试MySQL安装
- 解决MySQL数据库死掉以及拒绝服务的方法
- MySQL根用户root密码忘记后的处理方法
MYSQL 中的 MySQL 查找价格最高的图书经销商的几种SQL语句
出处:互联网 整理: 软晨网（RuanChen.com） 发布: 2009-09-13 浏览: 70 ::
收藏到网摘: n/a
不同的图书，在不同的经销商的价格不同，我们这里要找到每种图书最高的经销商是谁？ 找最低的类似了。 mysql> use test;
Database changed
mysql> CREATE TABLE shop (
-> article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL,
-> dealer CHAR(20) DEFAULT '' NOT NULL,
-> price DOUBLE(16,2) DEFAULT '0.00' NOT NULL,
-> PRIMARY KEY(article, dealer));
Query OK, 0 rows affected (0.13 sec)
mysql> INSERT INTO shop VALUES
-> (1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45),
-> (3,'C',1.69),(3,'D',1.25),(4,'D',19.95);
Query OK, 7 rows affected (0.03 sec)
Records: 7 Duplicates: 0 Warnings: 0
mysql> select * from shop;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
| 0001 | A | 3.45 |
| 0001 | B | 3.99 |
| 0002 | A | 10.99 |
| 0003 | B | 1.45 |
| 0003 | C | 1.69 |
| 0003 | D | 1.25 |
| 0004 | D | 19.95 |
+---------+--------+-------+
7 rows in set (0.06 sec)
mysql> select article,max(price) from shop group by article
-> ;
+---------+------------+
| article | max(price) |
+---------+------------+
| 0001 | 3.99 |
| 0002 | 10.99 |
| 0003 | 1.69 |
| 0004 | 19.95 |
+---------+------------+
4 rows in set (0.05 sec)
mysql> select article,max(price),dealer from shop group by article;
+---------+------------+--------+
| article | max(price) | dealer |
+---------+------------+--------+
| 0001 | 3.99 | A |
| 0002 | 10.99 | A |
| 0003 | 1.69 | B |
| 0004 | 19.95 | D |
+---------+------------+--------+
4 rows in set (0.00 sec)
mysql> select article,dealer,price from shop s1
-> where price=(select max(s2.price) from shop s2
-> where s1.article=s2.article);
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
| 0001 | B | 3.99 |
| 0002 | A | 10.99 |
| 0003 | C | 1.69 |
| 0004 | D | 19.95 |
+---------+--------+-------+
4 rows in set (0.01 sec)
mysql> select s1.article,dealer,s1.price
-> from shop s1
-> join(
-> select article,max(price) as price from shop
-> group by article) as s2
-> on s1.article = s2.article and s1.price = s2.price;
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
| 0001 | B | 3.99 |
| 0002 | A | 10.99 |
| 0003 | C | 1.69 |
| 0004 | D | 19.95 |
+---------+--------+-------+
4 rows in set (0.05 sec)
mysql> select s1.article,s1.dealer,s1.price from shop s1
-> left join shop s2 on s1.article=s2.article and s1.price select s1.article,s1.dealer,s1.price,s2.* from shop s1 left join shop s2
on s1.article=s2.article and s1.price
评论 (0) All
