c#下关于小数位数的一些实现方法集合，方便对c#小数位数控制的朋友。 1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.NumberDecimalDigits =intDecLength; //要设定的小数位数
double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值转成double
this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函数格式化小数位数
2.保留N位,四舍五入 .
decimal d= decimal.Round(decimal.Parse("0.55555"),2);
3.保留N位四舍五入
Math.Round(0.55555,2)
4,保留N位四舍五入
double dbdata = 0.55555;
string str1 = dbdata.ToString("f2");//fN 保留N位，四舍五入
5.保留N位四舍五入
string result = String.Format("{0:N2}", 0.55555);//2位
string result = String.Format("{0:N3}", 0.55555);//3位
6. 保留N位四舍五入 (不错)
double s=0.55555;
result=s.ToString("#0.00");//点后面几个0就保留几位



C#下如果显示保留小数位数，及百分号的解决方法:
1、用NumberFormatInfo类来解决:
System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.PercentDecimalDigits = 2;//小数点保留几位数.
provider.PercentPositivePattern = 2;//百分号出现在何处.
double result = (double)1 / 3;//一定要用double类型.
Response.Write(result.ToString("P", provider));
2、用toString方法.:
public string getRate(double hcount, double task)
{
string rValue;
string temp = "";
if (task == 0)
{
task = 1;
}
double db = (hcount / task) * 100;
if (hcount >= task)
{
rValue = "100%";
}
else
{
rValue = db.ToString("#0.#0") + "%";
}
return rValue;
}
string str1 = String.Format("{0:N1}",56789); //result: 56,789.0
string str2 = String.Format("{0:N2}",56789); //result: 56,789.00
string str3 = String.Format("{0:N3}",56789); //result: 56,789.000
string str8 = String.Format("{0:F1}",56789); //result: 56789.0
string str9 = String.Format("{0:F2}",56789); //result: 56789.00
string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89
string str12 =(56789 / 100).ToString("#.##"); //result: 567

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