当前位置: 首页 > 图文教程 > 网络编程 > PHP > 计算2000年01月01日起到指定日的天数

PHP
PHP技巧：详解phplib模板使用过程及运行原理
PHP技巧：Smarty+adodb分页示例
PHP技巧：PHP脚本中关于拼写检查函数库
PHP技巧：PHP脚本编程中的文件系统函数库
PHP技巧：PHP中几种删除目录的三种方法
学习PHP技术：txtSQL安装手册中文版
学习PHP：PHP的通用检测函数总结
详细学习PHP中对文件和目录的操作方法
PHP+MYSQL实例：网站在线人数的程序代码
Linux操作系统启动httpd失败的解决方法
初学：在PHP开发中如何使用Session？
PHP初学者遇到的中文乱码解决方案
PHP实例：实现文件上传的程序源码
PHP实例：常用的数值判断函数
PHP实例源代码：PHP实现翻页处理的类
PHP实例：从数组里筛选出重复的数据
PHP实例：用PHP实现windows风格的树型菜单
PHP实例程序：实现给上传图片加水印图案的做法
PHP实例：用PHP编写的网上调查投票系统
PHP实例：一个非常全面获取图象信息的PHP函数

No. « 5 6 7 8 »

技术文章搜索

关键字

PHP 中的 计算2000年01月01日起到指定日的天数

出处:互联网   整理: 软晨网（RuanChen.com）   发布: 2009-09-13   浏览: 38 ::
收藏到网摘: n/a

这是一个计算2000年01月01日起到指定日的天数的函数
<br>
(算头也算尾)日期格式为：YYYY-MM-DD
<br>
<?php
// 计算从2000年01月01日开始到某日的天数
function cal_start2end($end_day,$start_day)
{

$start_day=ereg_replace("-","",$start_day);
$end_day=ereg_replace("-","",$end_day);

if($end_day>=$start_day)
{ // 截止日期大于开始日期
if(substr($end_day,0,4)==substr($start_day,0,4))
{
if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;

// //同一年
if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$end_day-$start_day+1;
}
else
{
// not same month

switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
}
$endday_from_startday=$endday_from_newyear;
}
return ($endday_from_startday);
}
else
{
// 不同年！
$differ_year=substr($end_day,0,4)-substr($start_day,0,4);
$how_int_4_floor=floor($differ_year/4)+1; // 向下取整
$how_int_4_ceil=ceil($differ_year/4)+1; // 向上取整

if($how_int_4_floor==$how_int_4_ceil)
$how_leap_year=$how_int_4_floor-1;
else
$how_leap_year=$how_int_4_floor;
$how_noleap_year=$differ_year-$how_leap_year;
$differ_year2day=$how_noleap_year*365+$how_leap_year*366;

if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;

if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$differ_year2day+ substr($end_day,4,2);
}
else
{
// not same month

switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+1+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
} //End of switch

$endday_from_startday=$endday_from_newyear+$differ_year2day;
} //End of not same month

return ($endday_from_startday);

} //End of year
} //End of $end_day>=$start_day

} //End of function

$start_day="2000-01-01";
$end_day="2011-01-01";
echo "您输入的是：".$end_day."<br>\n";
$endday_from_startday=cal_start2end($end_day,$start_day);
echo "该日距离$start_day 共 ".$endday_from_startday." 天";
?>
<br><br><br><br>时间太少了，那位大虾可以修改为计算任意两日期之间的间隔最好！！！！！