当前位置: 首页 > 图文教程 > 网络编程 > PHP > 计算2000年01月01日起到指定日的天数

PHP
PHP 加密/解密函数 dencrypt(动态密文，带压缩功能，支持中文)
用mysql内存表来代替php session的类
简化php模板页面中分页代码的解析
一周让你学会PHP 不错的学习资料
PHP 数据库树的遍历方法
php实现从ftp服务器上下载文件树到本地电脑的程序
PHP 操作文件的一些FAQ总结
PHP 截取字符串 分别适合GB2312和UTF8编码情况
PHP 编程的 5个良好习惯
php下几个常用的去空、分组、调试数组函数
PHP Ajax中文乱码问题解决方法
php 采集书并合成txt格式的实现代码
php Try Catch异常测试
解决了Ajax、MySQL 和 Zend Framework 的乱码问题
Zend 输出产生XML解析错误
php动态生成JavaScript代码
隐性调用php程序的方法
在JavaScript中调用php程序
php 数组的创建、调用和更新实现代码
php生成SessionID和图片校验码的思路和实现代码

No. « 119 120 121 122 »

技术文章搜索

关键字

PHP 中的 计算2000年01月01日起到指定日的天数

出处:互联网   整理: 软晨网（RuanChen.com）   发布: 2009-09-13   浏览: 230 ::
收藏到网摘: n/a

这是一个计算2000年01月01日起到指定日的天数的函数
<br>
(算头也算尾)日期格式为：YYYY-MM-DD
<br>
<?php
// 计算从2000年01月01日开始到某日的天数
function cal_start2end($end_day,$start_day)
{

$start_day=ereg_replace("-","",$start_day);
$end_day=ereg_replace("-","",$end_day);

if($end_day>=$start_day)
{ // 截止日期大于开始日期
if(substr($end_day,0,4)==substr($start_day,0,4))
{
if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;

// //同一年
if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$end_day-$start_day+1;
}
else
{
// not same month

switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
}
$endday_from_startday=$endday_from_newyear;
}
return ($endday_from_startday);
}
else
{
// 不同年！
$differ_year=substr($end_day,0,4)-substr($start_day,0,4);
$how_int_4_floor=floor($differ_year/4)+1; // 向下取整
$how_int_4_ceil=ceil($differ_year/4)+1; // 向上取整

if($how_int_4_floor==$how_int_4_ceil)
$how_leap_year=$how_int_4_floor-1;
else
$how_leap_year=$how_int_4_floor;
$how_noleap_year=$differ_year-$how_leap_year;
$differ_year2day=$how_noleap_year*365+$how_leap_year*366;

if( is_int(substr($end_day,0,4)/4) )
$leap_day=29; //leap year
else
$leap_day=28;

if(substr($end_day,4,2)==substr($start_day,4,2))
{
// the same month
$endday_from_startday=$differ_year2day+ substr($end_day,4,2);
}
else
{
// not same month

switch (substr($end_day,4,2))
{
case "01":
$endday_from_newyear=substr($end_day,6,2)+1;
break;
case "02":
$endday_from_newyear=substr($end_day,6,2)+1+31;
break;
case "03":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31;
break;
case "04":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2;
break;
case "05":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30;
break;
case "06":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30;
break;
case "07":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*2+30*2;
break;
case "08":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*3+30*2;
break;
case "09":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*2;
break;
case "10":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*3;
break;
case "11":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*4;
break;
case "12":
$endday_from_newyear=substr($end_day,6,2)+1+$leap_day+31*5+30*5;
break;
} //End of switch

$endday_from_startday=$endday_from_newyear+$differ_year2day;
} //End of not same month

return ($endday_from_startday);

} //End of year
} //End of $end_day>=$start_day

} //End of function

$start_day="2000-01-01";
$end_day="2011-01-01";
echo "您输入的是：".$end_day."<br>\n";
$endday_from_startday=cal_start2end($end_day,$start_day);
echo "该日距离$start_day 共 ".$endday_from_startday." 天";
?>
<br><br><br><br>时间太少了，那位大虾可以修改为计算任意两日期之间的间隔最好！！！！！