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利用ASP从远程服务器上接收XML数据的方法
出处:互联网 整理: 软晨网（RuanChen.com） 发布: 2009-09-13 浏览: 64 ::
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复制代码 代码如下:
<%
dim objXML
dim objRootElement
dim strValue
dim strInetURL
dim strXML
dim item
strInetURL ="http://pf.inetsolution.com/inetactive2001/inetactive2001news.xml"
Dim HttpReq
set HttpReq = server.CreateObject("MSXML2.XMLHTTP")
HttpReq.open "GET", "http://pf.inetsolution.com/inetactive2001/inetactive2001news.xml", False
HttpReq.send
strXML = HttpReq.responseText
Set objXML = Server.CreateObject("Msxml2.DOMDocument")
objXML.validateonparse = true
objXML.async=false
objXML.loadXML(strXML)
if objXML.ParseError.errorCode <> 0 then
Response.Write("Error: " & objXML.parseError.reason & "<br>")
Response.Write("Code: 0x" & hex(objXML.parseError.errorCode) & "<br>")
Response.Write("At Line: " & objXML.parseError.line & "<br>")
Response.Write("At pos: " & objXML.parseError.linePos & "<br>")
else
set objRootElement = objXML.documentElement
if not isObject(objRootElement) then
Response.Write("no file loaded")
else
Response.Write(objRootElement.childnodes(0).text)
end if
end if
%>
dim objXML
dim objRootElement
dim strValue
dim strInetURL
dim strXML
dim item
strInetURL ="http://pf.inetsolution.com/inetactive2001/inetactive2001news.xml"
Dim HttpReq
set HttpReq = server.CreateObject("MSXML2.XMLHTTP")
HttpReq.open "GET", "http://pf.inetsolution.com/inetactive2001/inetactive2001news.xml", False
HttpReq.send
strXML = HttpReq.responseText
Set objXML = Server.CreateObject("Msxml2.DOMDocument")
objXML.validateonparse = true
objXML.async=false
objXML.loadXML(strXML)
if objXML.ParseError.errorCode <> 0 then
Response.Write("Error: " & objXML.parseError.reason & "<br>")
Response.Write("Code: 0x" & hex(objXML.parseError.errorCode) & "<br>")
Response.Write("At Line: " & objXML.parseError.line & "<br>")
Response.Write("At pos: " & objXML.parseError.linePos & "<br>")
else
set objRootElement = objXML.documentElement
if not isObject(objRootElement) then
Response.Write("no file loaded")
else
Response.Write(objRootElement.childnodes(0).text)
end if
end if
%>
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