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Javascript 中的 一个判断email合法性的函数[非正则]
出处:互联网 整理: 软晨网（RuanChen.com） 发布: 2009-09-12 浏览: 422 ::
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没用到正则，看起来这个函数的准确度还是比较高的。
<%
Function IsValidEmail(email)
Dim names, Name, i, c
IsValidEmail = True
names = Split(email, "@")
If UBound(names) <> 1 Then
IsValidEmail = False
Exit Function
End If
For Each Name In names
If Len(Name) <= 0 Then
IsValidEmail = False
Exit Function
End If
For i = 1 To Len(Name)
c = LCase(Mid(Name, i, 1))
If InStr("abcdefghijklmnopqrstuvwxyz_-.", c) <= 0 And Not IsNumeric(c) Then
IsValidEmail = False
Exit Function
End If
Next
If Left(Name, 1) = "." Or Right(Name, 1) = "." Then
IsValidEmail = False
Exit Function
End If
Next
If InStr(names(1), ".") <= 0 Then
IsValidEmail = False
Exit Function
End If
i = Len(names(1)) - InStrRev(names(1), ".")
If i <> 2 And i <> 3 Then
IsValidEmail = False
Exit Function
End If
If InStr(email, "..") > 0 Then
IsValidEmail = False
End If
End Function
%>
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